-- Determine the number of revolutions, vibrations, reciprocations,
or full oscillations in one second.
-- Multiply that number by (2 pi).
(550 - 200) rev per minute = -350 rev per minute / 60 sec per minute = (-35/6 rev per second) change in angular velocityAngular acceleration = (change in angular velocity) / (time for the change) =(-35/6 rev per second) x (2 pi radians per rev) / 4.5 seconds = -8.1449 radians per second2("Meters per sec sq" can't be a unit of angularacceleration, since angles can't be measured in meters.)
To find the angular size, we need to convert the distance to the object into radians. 4 yards is approximately 12 feet or 144 inches. The angular size can be calculated as the diameter of the object (1 inch) divided by the distance to the object (144 inches), which equals approximately 0.0069 radians.
If you have the mass, you can find the acceleration from Newton's Second Law, a=F/m where a is the acceleration, m is the mass, and F is the force. Then the velocity is given by the standard formula v=vo+at where v is the final velocity, vo the velocity at t=0, probably 0 in your case. If so v=at.
Velocity equal distance divided by time. For example, an object that traveled 5 metes in 10 seconds had a velocity of 5/10 meters per second which is .5 meters per second. Velocity is speed in a direction. Sometimes a navigate or positive number is sufficient as the direction. Other times you will need to be more specific, such as .5 meters per second East or 1.3 meters per second 30 degrees East of North.
The arc length is equal to the angle times the radius. This assumes the angle is expressed in radians; if it isn't, convert it to radians first, or incorporate the conversion (usually from degrees to radians) in to your formula.
Angular velocity has units of (angle per time), usually stated in radians per second. (1 whole revolution = 2 pi radians) Assuming the watch is operating properly, the second hand turns once per minute. 1 rev/minute = (2 pi) / (60 seconds) = pi/30radians per second. This is usually good enough for most physicists, but if they demand a number, it's easy to work it out: pi = 3.14159 (rounded) Angular velocity = pi/30 = 0.10472 radians per second. Or if you really want the physicist to take notice, tell him "104.72 milliradians per second".
By newton's second law: force = mass x acceleration. Acceleration can be found by the formula a = v2/r, or alternately, a = omega2 x r (where v is the speed, r is the radius, and omega is the angular velocity in radians/second).
They don't rotate in the same direction. But most of the rotation comes about from the conservation of angular momentum. Angular momentum is given by L=m*w*r2 where m is the mass, w is the angular velocity in radians per second, and r is the radius of the circular motion. Due to conservation of angular momentum, if the radius of the orbit decreases, then its angular velocity must increase (as the mass is constant). Hope I answered your question... You can find more on this website(I copied and pasted the info above): http://curious.astro.cornell.edu/question.php?number=416
1 revolution = (2 pi) radians1 minute = 60 seconds250 rpm = [ (250) x (2 pi) radians ] per [ 60 seconds ]= 26.18 radians per second (rounded)
It is 95.5 radians.
(550 - 200) rev per minute = -350 rev per minute / 60 sec per minute = (-35/6 rev per second) change in angular velocityAngular acceleration = (change in angular velocity) / (time for the change) =(-35/6 rev per second) x (2 pi radians per rev) / 4.5 seconds = -8.1449 radians per second2("Meters per sec sq" can't be a unit of angularacceleration, since angles can't be measured in meters.)
Assuming that "r" is the radius, that simply isn't sufficient information to calculate angular velocity.
You can use the relation that power equals torque times angular velocity. You start from the speed (rpm) and the horse power times 746 which gives the mechanical power in watts. To use the formula you have to use consistent units, which means torque is in Newton-metres and the angular velocity is in radians/second, in other words the rpm times 2.pi / 60. So the torque in Newton-metres is the power (watts) divided by the shaft speed in radians per second. T = (HP x 746) / (rpm x 2 x pi / 60) So if you know the speed and the power, you can find the torque.
The direction of angular acceleration comes from whether the angular speed of the object is clockwise or counterclockwise and whether it is speeding up or slowing down.The direction of the angular acceleration will be positive if the angular velocity is counterclockwise and the object's rotation is speeding up or if the angular velocity is clockwise and the object's rotation is slowing downThe direction of the angular acceleration will be negative if the angular velocity is clockwise and the object's rotation is speeding up or if the angular velocity is counterclockwise and the object's rotation is slowing downThe angular acceleration will not have a direction if the object's angular velocity is constant
To find the angular size, we need to convert the distance to the object into radians. 4 yards is approximately 12 feet or 144 inches. The angular size can be calculated as the diameter of the object (1 inch) divided by the distance to the object (144 inches), which equals approximately 0.0069 radians.
angular velocity s the rotational analague of linear velocity...direction of linear velocity s along tangent to the circle while that of angulr velocity s along the axis of rotation.the direction of angular v can be find by right hand rule which state that if the axis of rotation s held n right hand with fingers curled round the direction of rotation then the thumb will mark the direction of angular velocity.... the magnitude of angular velocity that s the angular speed is represented by the length of the line along the axis of rotation...its units are rad/sec,degrees/sec or revolution/sec while that of linear velocity s m/sec...
using the linear velocity of the points on the outside of gear 2,found in step b,and the radius of gear 2, find the gears angular velocity.