To find the distance traveled by a point on the edge of the wheel, we first need to calculate the average angular velocity. The wheel accelerates from 240 rpm to 360 rpm, so the average angular velocity is (240 + 360) / 2 = 300 rpm. Converting this to radians per second, we have 300 rpm × (2π rad / 1 min) × (1 min / 60 s) = 31.42 rad/s.
The wheel travels for 6.5 seconds, so the total angular displacement is 31.42 rad/s × 6.5 s = 204.23 radians. The circumference of the wheel is π × diameter = π × 0.33 m ≈ 1.04 m. Therefore, the distance traveled is 204.23 radians × 0.33 m/radian ≈ 67.39 m.
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
((60m/s+80m/s)/2)x12s=840m
The average speed of a car from 0 to 10 seconds can be calculated by taking the total distance traveled and dividing it by the total time taken. If the car accelerates uniformly from rest, you can use the formula for average speed, which is the final speed divided by 2. For example, if the car reaches a speed of 20 m/s at 10 seconds, the average speed would be 10 m/s. If more specific details about distance or acceleration are provided, a more precise calculation can be made.
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
160 m
The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.
0.07km
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
((60m/s+80m/s)/2)x12s=840m
The distance the car travels during the acceleration can be calculated using the formula: distance = (initial velocity)(time) + 0.5(acceleration)(time)^2. Plug in the values: initial velocity = 0 m/s, final velocity = 40 m/s, time = 8 s. Calculate the distance traveled during the acceleration.
The average speed of a car from 0 to 10 seconds can be calculated by taking the total distance traveled and dividing it by the total time taken. If the car accelerates uniformly from rest, you can use the formula for average speed, which is the final speed divided by 2. For example, if the car reaches a speed of 20 m/s at 10 seconds, the average speed would be 10 m/s. If more specific details about distance or acceleration are provided, a more precise calculation can be made.
The distance traveled by the car can be calculated using the equation (s = \frac{1}{2}at^2), where (s) is the distance, (a) is the acceleration, and (t) is the time. Plugging in the values, we have (s = \frac{1}{2} \times 10 \times (4)^2 = 80) meters. Therefore, the car will travel 80 meters in 4 seconds.
The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).The question does not specify how many seconds it accelerates for so I would suggest that the answer is 300,000 km per second (approx).
No