Want this question answered?
Which of the following is a disadvantage to using equations?
A table, a graph, and an equation.
Divide any number in the second set by the corresponding number in the first set.
A linear non-proportional relationship can be identified from a table if the ratios of the y-values to the x-values are not constant. In other words, if the values in the y-column do not increase or decrease by the same factor for each increase in the x-values. From a graph, a non-proportional linear relationship can be identified if the line does not pass through the origin (0,0) or if the slope of the line is not constant. Finally, in an equation, a non-proportional linear relationship can be identified if it does not have a multiplier or constant ratio in front of the x-variable.
You could put the equation in slope-intercept form or in parent linear function or even make a table of values.
In a table, divide a number in one column by the corresponding number in the other column. In a graph it is the gradient of the line. The equation, for the variables X and Y will be of the form Y = mX and the constant of proportionality is m.
Divide an entry for one variable in the table by the corresponding entry for the other variable.
There are three ways: a table, a graph, and an equation.
If the relationship between two variables in a table is that of direct variation, then the unit rate or the constant of proportionality is determined by dividing any non-zero value of one of the variables by the corresponding value of the other variable.
Graph and Table: http://i50.tinypic.com/szhr4k.png
equation, table or a graph
Which of the following is a disadvantage to using equations?
A table, a graph, and an equation.
Divide any number in the second set by the corresponding number in the first set.
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
In general you cannot. Any set of ordered pairs can be a graph, a table, a diagram or relation. Any set of ordered pairs that is one-to-one or many-to-one can be an equation, function.