You don't
You cannot. You do not have the necessary information.
weight x distance = work
The formula for finding work is: Work = force X distance. To find distance, you must divide both sides by force. After simplifying the equation, the new equation will read: distance = work divided by force
First you have to find the force F=(mass/weight of object)*(9.8) Once you find force Work=(Force)*(Distance) Your answer will be in joules
Energy or "work" The formula is Energy transferred or work done is equal to the force needed times the distance moved Wd = F x d
I'm fairly sure that you can't. Not without the acceleration or the time, at least.
You need one more "given": the time, i.e., how long it takes you. Work = distance x force, and power = work / time. Thus, you get: power = distance x force / time
W=Fd so when you divide both sides by Force and Work and take the reciprocal you get the equation F=W/d -Joshua Garrison
W = f.s Work = force x distance w in neuton metres
Weight has same dimension and unit as force. Distance has same dimension and unit as displacement. So weight * distance has same dimension and unit as force * displacement. Force * displacement is work done by the force. Work divided by time to do the work is Power. So weight * distance divided by time also has same dimension and unit as Power although it is not power. S.I. unit of weight * distance divided by time is Newton *meter/second or Nms-1 (in abbr.) It's dimensions are 1, 2, -3 in mass, length and time respectively. Note that given quantity's unit can't be joule/second or watt because weight * distance is not work done, only unit and dimension are same1 . 1. Two physical quantities may have same dimensions and units but that doesn't mean they refer to same quantity.
Work = force x distance;force = work/distance = 2500/100 = 25 Newtons weight which is about 2.5 kg mass
You can't. Work is (force) times (distance), so you have to know something about the force. Just knowing the mass doesn't tell you anything about the force ... unless there's actually something else about the mass that you've overlooked.