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5x - 9y = 43 (A)3x + 8y = 68 (B)


(A)*3: 15x - 27y = 129

(B)*5: 15x + 40y = 340

Subtracting the first from the second gives

67y = 211 => y = 211/67 = 3.15 approx


Substituting the [rational] value of y in (B)

5x - 9*211/67 = 43 => 5x = 43 + 1899/67 = 4780/67

therefore x = 956/67 = 14.27 approx.


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Q: How do you find graph cordinates in this problem 5x-9y equals 43 3x plus 8Y equals 68?
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