[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
No translation will invert a quadratic graph.
The highest point on a graph is when the derivative of the graph equals 0 or the slope is constant.
Any graph with the slope of -1/2
There needs to be an x variable to create a graph.
Yes, that is a shifted tanX graph, just as you would shift any graft.
Answer: You must switch all your letters and numbers around... to where your problem is y=-2x+2. Than after you get your answer, for the problem, Graph it... to graph it, you would take your b (+2) and find it on the graph, than you would take your m (-2) and find it on the graph, but! you must make sure it is a fraction so you will have to find two numbers and graph your second number, than make a STRAIGHT line on your point, all the way across your graph.
to find cordinates
The graph is a parabola facing (opening) upwards with the vertex at the origin.
you should watch that the graph equals 100 percent
Displacement is the area under the v-t graph.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
the graph is moved down 6 units
It is a straight line with gradient -A/B and intercept C/B.
The graph shifts downward (negative y) by 9 units.
The slope of the graph does not exist. And in the context of "this" problem it means absolutely nothing.
The displacement on a velocity-time graph is the area beneath the line.
You graph each of them separately, on the same coordinate plane.
y=x+1 there for answer is 2