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try it out in real life, or draw it out. Basically if you have 5 people at the party and every one shakes hands (if this is what you mean) you could do this: draw 5 dots in a circle, and draw a line between every single dot, count the lines and voila you have your answer
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If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?
107 unique handshakes will be exchanged
15 friends at a party and all kisses each other then how many kisses?
This is a variation on the handshake problem which say if there are n people at a party and every one shakes hands with every other one, how many handshakes are there? It is well know that kisses in fact are cleaner than handshakes which to tend to pass diseases. So thanks for a cleaner version of this classic math problem! n(n-1)/2 is the formula for the number of handshakes OR kisses for n people at a party. If you case, 15x14/2 which is 15x7 or 105.
Prove that total number of people who lived on earth and made odd number of handshakes is always even?
If you multiply anything by 2 it always comes out even. So if people make 35 handshakes, we multiply it by 2 and we get 70 people. This will work with any different number of handshakes, odd or even.
If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
How many people were at a party if There were 105 handshakes at a party and if each person at the party shook hands with exactly once with every other person.?
15 (15 * 15 - 15)/2 = 105
If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?
107 unique handshakes will be exchanged
there are 3 people at a party if each person mis shake hands with every person at the party exactly once how many handshakes will there be?
So, there will be 3 handshakes among the 3 people at the party.
There are 3 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?
With 3 people, there are only 3 handshakes: AB, AC, and BC. Where it gets interesting is at a party with, say, 10 people ... 45 handshakes. Or in the US Senate when all 100 Senators are present ... 4,950 handshakes.
If there are 8 people at a party and every person shakes hands with everyone else at the party how many handshakes will there be?
There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.
If ten people are at a party and they all exchange handshakes how many hand shakes were exchanged?
If that happens you have to times ninexten and the answer would be 90 handshakes
Seve girls arrive at a tea party each of them shakes hands once with each of the others how many handshakes does that make?
21 handshakes
If there 28 handshakes how many people are at the party?
29 People including You.
At certain party there wereb 45 handshakes Everyone shook hands with everyone else exactly once how many people attended the party?
There were ten people at the party. This is a triangular sequence starting with two people: 1, 3, 6, 10, 15, 21, 28, 36, 45, etc. There's an equation for this. With n people at the party, the number of handshakes is n(n-1)/2.
How many people are at a party with 741 handshakes if everyone shakes once?
371
15 friends at a party and all kisses each other then how many kisses?
This is a variation on the handshake problem which say if there are n people at a party and every one shakes hands with every other one, how many handshakes are there? It is well know that kisses in fact are cleaner than handshakes which to tend to pass diseases. So thanks for a cleaner version of this classic math problem! n(n-1)/2 is the formula for the number of handshakes OR kisses for n people at a party. If you case, 15x14/2 which is 15x7 or 105.
If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?
Sixty-six unique, distinct handshakes.
If at a party there are a total of 741 handshakes and each person shakes hands with everyone else at the party exactly once how many people are at the party?
38
