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If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?
107 unique handshakes will be exchanged
15 friends at a party and all kisses each other then how many kisses?
This is a variation on the handshake problem which say if there are n people at a party and every one shakes hands with every other one, how many handshakes are there? It is well know that kisses in fact are cleaner than handshakes which to tend to pass diseases. So thanks for a cleaner version of this classic math problem! n(n-1)/2 is the formula for the number of handshakes OR kisses for n people at a party. If you case, 15x14/2 which is 15x7 or 105.
Prove that total number of people who lived on earth and made odd number of handshakes is always even?
If you multiply anything by 2 it always comes out even. So if people make 35 handshakes, we multiply it by 2 and we get 70 people. This will work with any different number of handshakes, odd or even.
If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
How many people were at a party if There were 105 handshakes at a party and if each person at the party shook hands with exactly once with every other person.?
15 (15 * 15 - 15)/2 = 105
