You're supposed to know that in every right triangle,
(one leg)2 + (the other leg)2 = (hypotenuse)2 .
Subtract (one leg)2 from each side of this equation, and you'll have:
(the other leg)2 = (hypotenuse)2- (one leg)2
You know both of the numbers on the right side. Do you think you can
subtract them and figure out the number on the left side ?
The hypotenuse leg of a right angle triangle is its longest side.
The hypotenuse of a 30-60 right triangle if the short leg is 2992 is: 5984
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The hypotenuse of a right triangle with legs of 5cm and 2.5cm is: 5.59cm
Longest leg of a right triangle. *hypotenuse
If the hypotenuse and a leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
congruent; hypotenuse and a leg
The hypotenuse leg of a right angle triangle is its longest side.
A right triangle with one leg 2.968 and other leg 3.504 will have a hypotenuse of 4.592
The hypotenuse is the square root of (82 +152) = 17.
In a right triangle with a hypotenuse of 11 and one leg of 8, the other leg is: 7.55
If it's a right angle triangle and an acute angle plus the length of a leg is given then use trigonometry to find the hypotenuse.
The hypotenuse dimension for a right triangle with 3 and 4 leg dimensions is: 5
The hypotenuse of a 30-60 right triangle if the short leg is 2992 is: 5984
A right triangle has a hypotenuse of 12cm and a leg that is 9cm the other leg would be 7.94. This is a math problem.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)