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By using the equation of a straight line y = mx+b whereas m is the slope of the line and b is the y intercept

Q: How do you find point slope form of a line?

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You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.

Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.

Related questions

You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.

You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.

By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).

Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

No line described, but here is the point slope form. Y - Y1 = m(X - X1) =============