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Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

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y = -2x+1

Q: Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?

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Choose the equation of the line that contains the points (1, -1) and (2, -2).

No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.

Equation: y-3 = -5(x-6) => y = -5x+33

y-9 = 3(x-4) y = 3x-3 in slope intercept form

If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5

Related questions

y = 2x + 1.

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3

y = 2x - 1

y=2x+1

The answe iss..... 6

It is: y = 2x-6

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

As a straight line equation: y = -3x+18 in slope intercept form

It is: y-7 = 2(x-3) => y = 2x+1

Choose the equation of the line that contains the points (1, -1) and (2, -2).