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If the image produced is 4 times the size of the object and inverted, then the object is placed at a distance equal to half the radius of curvature from the mirror. This would position the object beyond the center of curvature of the concave mirror. Using an accurate scale, you would measure a distance of half the radius of curvature from the mirror to locate the object.
For a convex mirror, the focal length (f) is half the radius of curvature (R) of the mirror. This relationship arises from the mirror formula for convex mirrors: 1/f = 1/R + 1/v, where v is the image distance. When the object is at infinity, the image is formed at the focal point, and the image distance is equal to the focal length. Hence, 1/f = -1/R when solving for the focal length in terms of the radius of curvature for a convex mirror.
radius of curvature is double of focal length. therefore, the formula is: 1/f = (n-1)[ 1/R1 - 1/R2 + (n-1)d/nR1R2] here f= focal length n=refractive index R1=radius of curvature of first surface R2=radius of curvature of 2nd surface d=thickness of the lens using this, if you know rest all except one, then you can calculate that.
The mirror equation for concave mirrors is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. Since the object distance is 10 cm from the mirror and the radius of curvature is 30 cm, the focal length (f) is half the radius of curvature, which is 15 cm. Substituting the values, you can find the image distance (di) which is -20 cm (negative indicates a real image). The magnification can be calculated using M = -di/do, which in this case is -20/-10 = 2. This means the image is inverted and magnified by a factor of 2, located at a distance of 20 cm on the same side as the object from the mirror.
The object must be placed at a distance equal to the radius of curvature of the concave mirror in order for its image to be at infinity. In this case, the object must be placed 28.6 cm away from the concave mirror.
The image of the star will be 67.5 cm from the mirror because focal length is the raidus of curvature multiplied by 2 or (2)(C). So, therefore, 150 / 2 will give the focal length which would also be the answer.
A convex lens forms a real and inverted image of equal size only when it is kept at the center of curvature of the lens. The image is also formed at the center of curvature at the other side. Hence, the distance of object = distance of image = 50 cm. Now, focal length = � � radius of curvature = � � 50 cm = 25 cm Hope it is clear!
Distance from the mirror, curvature of the mirror.
Distance from the mirror, curvature of the mirror.
The focal length of a concave mirror to form a real image is positive. It is equal to half the radius of curvature (R) of the mirror, and the image is formed between the focal point and the mirror.
The object is located between the focal point (F) and the center of curvature (C) of a concave mirror. This position of the object would result in an inverted and magnified image being formed behind the mirror. The distance from the object to the mirror must be greater than the focal length but less than the radius of curvature.
The equations used to calculate the focal length (f) and image distance (d) of a plano-convex lens are: For focal length (f): 1/f (n - 1) (1/R1) where: f is the focal length of the lens n is the refractive index of the lens material R1 is the radius of curvature of the curved surface of the lens For image distance (d): 1/f 1/do 1/di where: do is the object distance from the lens di is the image distance from the lens These equations are fundamental in understanding the behavior of light passing through a plano-convex lens.