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Q: How do you find sq root?

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it is under root: l sq. + b sq. + h sq.

72.6636084983398

sq. root of 75 = sq. root of (25 x 3) = (sq. root of 25)(sq. root of 3) = 5(sq. root of 3)

Square root of 0.0625 is 0.25

Find the factors of 484484= (4)(121)Square root of (484) = Sq. root (4 x 121) = Sq. root (4) x sq. root of (121) = 2(11) = 22

sq. root of (80/125)= sq. root of [(9)(2)(5)/(25)(5)]= (sq. root of 9)(sq. root of 2)/sq. root of 25= (3/5)sq. root of 2

sq root (112.7) = 10.6160256.... sq root (112.7) = 10.6160256....

It is the square root of 30

11.18033989 is the sq. root of 125.

Sq root of 2 * sq root of 8 = 1.414 * 2.828 = 3.998792

sq. rt. of 28 = 5.291502622

4

Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36

3.5714

There are three equations that are in most common use in the electrical trade to find current. They are I = W/E - Amps = Watts/Volts, I = E/R - Amps = Volts/Resistance and I = Sq Root of W/R - Amps = Sq Root of Watts/Resistance

Searching Google with "square root of 396" gave 19.8997487421 (round to 19.9). To discover the method used to calculate the sq root, search Google.

Square root of 6 = 2.44948 Sq root of 6 + Sq root of 6 = 2.44948 + 2.44948 = 4.89896

(3 root 7) squared = (3 root 7) (3 root 7) = (3x 3) ( sq root 7 x 7) = 9 x sq root 49 = 9 x 7 = 63

sq. root of 98 =sq. root of 49*2 =7*sq.root of 2 =7*1.414 =9.898

The formula you are looking for is I = sq root of W/R.

No. The sq root of 84 is 9.16555515139. 81 is a perfect square, where the sq root is 9.

If you are using integers, it is prime. x2 - 45 can be factored as the difference of squares IF you use irrational numbers (sq roots) Ex x2 - 16 = (x + 4)(x - 4) ..... notice 4 is sq root of 16 so you can sreate a rule... x2 - A = (x + sq root A)(x - sq root A) So ... AND THIS IS SOMETHING NO HIGH SCHOOL BOOK EVER TEACHES.... x2 - 45 = (x + sq root 45)(x - sq root 45) You should simplify the sq root 45 to be (3 times sq root 5) in both factors.

f(x)=x2f -1(x)=sq. root(x)__________________y2=x [invert y](y2)-1=x = 1/y2=xsq. root(1/y2)= sq. root (x) [y can't be squared, root both sides](1/y)=sq. root(x)y-1=sq. root(x)

if you know the area, square root on your calculator. therefore sq(4)= 2 sq(9)=3

± 207.364414