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y = x2 - 2
Set y = 0
0 = x2 - 2
0= x2 - (sq. root of 2)2
0 = [x - (sq. root of 2)][x + (sq. root of 2)]
x - (sq. root of 2) = 0 or x + (sq. root of 2) = 0
x = (sq. root of 2) or x = -(sq. root of 2)
Thus, the x-intercepts are +&- sq. root of 2.
X intercept: -5 Y intercept: +3
12
y intercept is 1 x intercept is .5
The y intercept is 10 and the x intercept is -4
For the x intercepts, y = 0 ie 0 = 2x2 + 2x - 4 or x2 + x - 2 = 0 so that (x + 2)*(x - 1) = 0 So the intercepts are (-2,0) and (1,0)