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Q: The x intercepts of y equals x2-2?

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y intercept is 1 x intercept is .5

Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.

To find x, sub 0 in for y. To find y, sub 0 in for x.y= -10, x= 4

x + 2y = 10At the x-intercept, y=0:x = 10At the y-intercept, x=0 ==> 2y = 10y = 5

y = 0 gives 0 = - x - 20 so that x = -20 So the intercept is (-20, 0)

Related questions

X intercept: -5 Y intercept: +3

12

The 'x' and 'y' intercepts of that equation are both at the origin.

y = -xBoth intercepts are at the origin. From there, the line slopes up to the leftand down to the right.

5x²=0 X=0 the function y=5x² only intercepts x when x = 0

y intercept is 1 x intercept is .5

The y intercept is 10 and the x intercept is -4

x intercept = 5 y intercept = 15

-16

There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.

The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.

For the x intercepts, y = 0 ie 0 = 2x2 + 2x - 4 or x2 + x - 2 = 0 so that (x + 2)*(x - 1) = 0 So the intercepts are (-2,0) and (1,0)

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