The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
540 degrees
The sum of the interior angles of a pentagon is 180*(5-2) = 180*3 = 540 degrees. The size of the pentagon is totally irrelevant.
540 degrees
520 Degrees
A pentagon
The sum of the five interior angles of ANY pentagon is 540 degrees.If the pentagon is regular, then each angle is 108 degrees.
find the sum of the measures of the interior angles of 13-gon.
(n-2)x180 = 540 degrees.
Sum_of_interior_angles = 180o x (number_of_sides - 2) So for a pentagon with 5 sides: sum = 180o x (5 - 2) = 540o
The sum of the interior angles is 540 degrees. Within that constraint the angles can have any value.
360 degrees
The 5 angles add up to 540 degrees and each interior angle measures 108 degrees