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82 + 152 = 64 + 225 = 289 = 172 So, by Pythagoras, the cross section of the prism is a right angled triangle.

So cross-sectional area of the prism is 8*15/2 = 60 square units.

So area of two "ends" is 120 square units.

Area along the height = (8+15+17)*5 = 40*5 = 200 square units so total surface area = 120 + 200 = 320 square units.

It is not necessary to prove that the end face is a right angled triangle but doing so makes it easier to calculate its area.

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Q: How do you find surface area of a prism with edges 8 15 17 and height 5?
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