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First you must determin what the "apothem" is, and by that i mean what the hell that word means.
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∙ 10y ago
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A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of?
Area in square units = 0.5*(apothem)*(perimeter)
Find the area of a regular 7-gon with a side length of 12?
You can find the area of any regular polygon with this equation: 1/2ap where a is the apothem and p is the perimeter.To find the perimeter, multiply 7 times 12 to get 84.To find the apothem, divide 360 (the amount of degrees around the center of the polygon) by 7 (the amount of sides you have) to get about 51.43. This gives you the measure of the angle of one triangle connected to 2 adjacent vertices. You have to make this a right triangle so that you can use trigonometry to find the apothem, so divide that angle by 2 to get 25.72. You know the side opposite of this angle is 6 because it is half the amount of the side (remember we divided this triangle by 2). To find the apothem at this point, use trigonometry. tan25.72 = 6/x. The apothem is 12.46.So, plug all of this into your calculator; a = 1/2(84)(12.46). You find the area to be about 523.3.
Apothem in a regular pentagon with an area of 87.5 in2 and a side of 5 in?
7
What is the area of a regular pentagon with 7 inch sides and an apothem of 3.9 inches?
If you mean an apothem of 4.82 inches rounded to two decimal places then its area is 0.5*4.82*7*5 = 84.35 square inches.
What is the area of an regular octogon with a apothem of 7 and a side length of 5.8?
Area of regular 8 sided octagon: 0.5*7*5.8*8 = 162.4 square units Not that in fact by using trigonometry the apothem is slightly bigger than 7
How do you find the area of a nonagon?
In general you would need to select a vertex of the nonagon and join it to the other vertices (except the two adjacent ones). This will divide the nonangon into 7 triangles. Measure the sides and/or angles of these triangles and calculate their areas. Add these together to get the area of the nonagon.If the nonagon is regular then there are formulae to calculate its area. These depend on whether you know the side length, apothem or circumradius.
A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of?
Area in square units = 0.5*(apothem)*(perimeter)
Find the area of a regular 7-gon with a side length of 12?
You can find the area of any regular polygon with this equation: 1/2ap where a is the apothem and p is the perimeter.To find the perimeter, multiply 7 times 12 to get 84.To find the apothem, divide 360 (the amount of degrees around the center of the polygon) by 7 (the amount of sides you have) to get about 51.43. This gives you the measure of the angle of one triangle connected to 2 adjacent vertices. You have to make this a right triangle so that you can use trigonometry to find the apothem, so divide that angle by 2 to get 25.72. You know the side opposite of this angle is 6 because it is half the amount of the side (remember we divided this triangle by 2). To find the apothem at this point, use trigonometry. tan25.72 = 6/x. The apothem is 12.46.So, plug all of this into your calculator; a = 1/2(84)(12.46). You find the area to be about 523.3.
Apothem in a regular pentagon with an area of 87.5 in2 and a side of 5 in?
7
What is the area of a regular octagon with a side length of 5.8 centimeters and a apothem of 7 centimeters?
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
What is the area of a regular pentagon with 7 inch sides and an apothem of 3.9 inches?
If you mean an apothem of 4.82 inches rounded to two decimal places then its area is 0.5*4.82*7*5 = 84.35 square inches.
What is the area of an regular octogon with a apothem of 7 and a side length of 5.8?
Area of regular 8 sided octagon: 0.5*7*5.8*8 = 162.4 square units Not that in fact by using trigonometry the apothem is slightly bigger than 7
What is the area of a regular octagon with a side length of 5.8 centimeters and an apothem length of 7 centimeters?
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
How do you find the area of a regular octagon with a apothem of 7 inches and a side length of 5.8 inches. And rounded to the nearest tenth.?
The area is 162.4 square inches.If apothem = x, then area = 8*x^2*tan(180/8)If side = s, then area = 8*s^2/(4*tan(180/8))
A regular octagon with sides of length 7 and an apothem of length 8.45 has an area of how many square units?
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s (apothem times one-half the perimeter)So for this example, (7 cm and 8.45 cm) Area = (8.45)(28) = 236.6 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 7 cm , the area is also about 236.6 cm2.(This formula is generated by adding or subtracting the missing corner triangles.)
A regular octagon with sides of length 7 and an apothem of length 8.45 has an area of what?
The area of a regular octagon: A = (2 x apothem)2- (length of side)2 or in this case A= (2 x 8.45)2 - 72
A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of square units?
293.72
