Q: What numbers can go into 117 and 195?

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1, 3, 13, 39

195-78 = 117

5x39=195

1, 3, 9, 13, 39, 117

1, 3, 9, 13, 39, 117

117

117

It is: 13

3 and 9

Their LCM is 117

585 is divisible by these numbers: 1 3 5 9 13 15 39 45 65 117 195 and 585.

The GCF is 39.

39, 78, 117, 195, 312 and 936 are divisible by three.

They are: 1 and 9

9*13 = 117

It has 195-78=117 neutrons. (mass no. - no. of protons) 117 neutrons.

585 is divisible (without remainders) by: 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585.

The amount after the discount is 117.

The atomic number of platinum is 78. So there are 78 protons. The number of neutron depends on the isotope. Pt-195 will have 117 neutrons (195 - 78 - 117)

Do you mean what two consecutive odd numbers gives a product of 195? If so then: 13*15 = 195

39, 78, 117, 156, 195.

An infinite number. 117, 234, 351, 468, 585, 702, 819, 936, 1053 +117 . . .

They are: 9*13 = 117 and 117/9 = 13

There are none. The only two consecutive numbers totaling -195 are -98 and -97.

13 x 9 = 117

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