Problem Statement for LCM:
Enter Two digits by a user and get its LCM
Answer:
#include
#include
void main()
{
int x,y,i,j;
clrscr();
printf("Enter Two Digits");
scanf("d",&x,&y);
for(i=1;i<=x;i++)
{
for(j=1;j<=y;j++)
{
if(y*i==x*j)
{
printf("LCM is %d\n",y*i);
i=i+x;
}
}
}
getch();
}
OR
there will be another easy way to solve it...
Answer:
#include
#include
void main()
{
int x,y,i,;
clrscr();
printf("Enter Two Digits = ");
scanf("d",&x,&y);
for(i=1;i<=x*y;i++) {
if(i%x==0&&i%y==0)
{
printf(LCM is %d",i);
break;
}
}
getch();
}
lcm(a,b,c,d) = lcm(lcm(a,b,c),d) = lcm(lcm(a,b),lcm(c,d))
You cannot find the LCM of one number. There must be two numbers to compare, because the C means common.
If C is co-prime with 6 and with 7, then LCM(6, 7, C) = 42*C If not, the answer depends on the value of C.
That would depend on the value of C.
If they have no common factors other than 1, the LCM is their product.
The C stands for Common.
That depends on the values of A, B and C.
Find the LCM of the first two numbers and then find the LCM of that number and the third one. That answer will be the LCM of all three.
To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.
You need at least two numbers to find an LCM.
Two or more numbers are needed to find the LCM
You need at least two numbers to find an LCM.