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Factor them.

k2 = k x k

k2 - 1 = (k - 1)(k + 1)

k2 - 2k + 1 = (k - 1)(k - 1)

Combine the factors, eliminating duplicates.

k2(k + 1)(k - 1)(k - 1) = k5 - k4 - k3 + k2, the LCM

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Q: How do you find the LCM of k to the 2nd power k to the 2nd power-1 and k to the 2nd power minus 2k plus 1?
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