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The important property of a rhombus to note is that a rhombus has all sides of equal length. Then:

Let the vertices be A, B, C, D; let the diagonal BD be the same length as the sides.

Consider the triangle ABD formed by two sides of the rhombus and the diagonal BD. As all sides are equal in length, it must be an equilateral triangle and thus each angle can be calculated, in particular angle BAD of the rhombus.

Consider the triangle BCD formed by the other two sides of the rhombus and the diagonal BD. The angle BCD of the rhombus can also be calculated as above.

For angles ABC and CDA of the rhombus, note that angle ABC is the same as the sum of angles ABD and DBC. and those angles can be calculated above; similarly for angle CDA.

A short cut that can be used is the property of a rhombus that opposite angles of a rhombus are equal which means once angle DAB has been calculate, BCD is then known. Then by subtracting the sum of these from 360o (the sum of the angles of a quadrilateral and a rhombus is an quadrilateral) and dividing the result by 2 will give the other two angles..

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Q: How do you find the angles of a Rhombus given that one diagonal is equal to one of its side?
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