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Q: How do you find the area of a cylinder using it's circumference?

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you divide the surface area by the circumference.

Find the radius by dividing the circumference by 2pi then find the area of the base and multiply it by the height

Entire surface area of a cylinder = (2*pi*radius^2)+(circumference*height) If you are given the circumference then radius = circumference/2*pi

We assume the surface area of a cylinder excluding its ends. Area = height of cylinder multiplied by circumference. That is A = h x Pi x diameter.

Circumference = 2*radius Area = 2*pi*radius2 Area = 2*pi*(circumference/2)2

Pi is the number of times the diameter of a circle will fit into the circumference. Pi is not a circle, and does not have a circumference or area. To calculate a circumference USING pi, the circumference is diameter * pi. To find the area using pi, area = pi * radius * radius

First of all, find the area of the circle on top of the cylinder, using the formula... pi x radius^2 ... Multiply that by two because there are two circles on the cylinder. Then find the area of the rest of the cylinder, which is basically a rectangle. So, get the height, and multiply it by the circumference of the circle (also the length of one side of the rectangle) using the formula ... pi x diameter ...

divide the circumference by pi (3.1416) and divide the product by two that will give you the radius

What do you have? The area of the circle or the circumference? Area: divide the area by pi, then square root it Circumference: divide the circumference by 2 then divide it by pi

To find the lateral area of a cylinder, multiply the circumference (πd) by the height (πdh). After you have this, you can find the total surface area by adding twice the area of the base (2πr2).(Lateral area = πdh), (Surface area = πdh + 2πr2).

If you know the circumference then divide that by (2 x pi) and you will get the radius. The width is unnecessary information.

Find the circumference of the circles (the ends) and multiply it by the height of the cylinder. Then add that to the area of the ends.

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