you find the area of a koch snowflake using z=(n-1)x/3
Technically, you can't. The Koch snowflake is self-similar. So the perimeter is infinity.
1904
yes! the best example would be the Koch snowflake.
Yes.
It is a fractal: each enlargement of the snowflake is an identical image.
Yes - as you "zoom in" on the sides of the snowflake, the same pattern occurs infinitely.
an infinite number.
For a fixed area, the perimeter is minimum for a circle, but has no maximum. Fractal figures (such as Koch snowflake) may have a finite area within an infinite perimeter.
Either the koch snowflake or the Sierpinski triangle
Koch's snowflake is a fractal and a mathematical curve that starts with an equilateral triangle. Iteratively, each side of the triangle is divided into three equal segments, and an equilateral triangle is constructed on the middle segment, creating a star-like pattern. This process is repeated indefinitely, resulting in a shape with an infinitely increasing perimeter while enclosing a finite area. The snowflake exemplifies the concept of self-similarity and is a classic example in the study of fractals.
It depends on what the side lengths are for the first triangle
A variety of such shapes can be constructed; a well-known example is the Koch snowflake. http://en.wikipedia.org/wiki/Koch_snowflake