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How do you work out the perimeter of the Koch snowflake fractal?
Technically, you can't. The Koch snowflake is self-similar. So the perimeter is infinity.
When was the Koch Snowflake created?
1904
Do all fractals have an infinite perimeter and finite area?
yes! the best example would be the Koch snowflake.
Is the Koch Snowflake self-similar?
Yes.
What is special characteristic of koch snowflake?
It is a fractal: each enlargement of the snowflake is an identical image.
Is the Koch Snowflake a fractal?
Yes - as you "zoom in" on the sides of the snowflake, the same pattern occurs infinitely.
How many iterations are in the koch snowflake?
an infinite number.
What is the relationship between the perimeter and area when area is fixed?
For a fixed area, the perimeter is minimum for a circle, but has no maximum. Fractal figures (such as Koch snowflake) may have a finite area within an infinite perimeter.
What is the name of the most famous fractal triangle?
Either the koch snowflake or the Sierpinski triangle
What is the side length of the stage three Koch snowflake?
It depends on what the side lengths are for the first triangle
What is the shape whose perimeter has infinite length?
A variety of such shapes can be constructed; a well-known example is the Koch snowflake. http://en.wikipedia.org/wiki/Koch_snowflake
What is this answer The von koch snowflake is constructed by starting with the line segments forming aan A Rectangle B equilateral triangle C square D area boundary?
The von Koch snowflake is infact a fractal that looks like a snowflake. It is made by starting with an equilateral triangle. The next step is to remove the middle third of each line and add two edges of the same length as the removed segment across the gap. Now all 12 of the edges are equal length and the whole shape should now look like the star of David. Now remove the middle of third of each of the twelve edges and add another "spike" to each. Keep repeating this over and over ad infinitum and you have the Koch snowflake.
