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How do you find the area of a rectangle tennis court if it has 480 feet perimeter. the length of the court is 6 feet more than twice the width?
Wiki User
∙ 12y ago
480 = 2w + 2L
=> 2w = 480 - 2L
=> w = 240 - L
=> L = 240 - w
6 + 2w = L
2w = L - 6
2w = (240 -w) -6
3w = 234
w = 78
therfore 78+78 + 6 = L
L = 162
162+162+78+78 = 480
So: The area is 78*162 = 12,636 sq.ft.
Wiki User
∙ 12y ago
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The basketball court in the park is a rectangle. Two of the sides are 84 feet long and the other two sides are 50 feet long. What is the perimeter of the basketball court?
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