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As it's an isosceles right triangle, the right angle is the angle between the two sides of equal length.

Using Pythagoras, the lengths of these sides, and hence the area can be found:

2 x side2 = (6√2)2

⇒ side2 = 62

⇒ side = 6

⇒ area = 1/2 x 6 x 6

= 18 sq units.

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Q: How do you find the area of an isosceles right triangle with hypotenuse 6sqrt2?
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