No, the sum of the legs of a triangle have to be greater than the hypotenuse.
Using Pythagoras' theorem
It is a triangle whose interior angles are 45, 45 and 90 degrees
A 45-45-90 triangle is an isosceles right angled triangle. If its two short sides are of length x units then, by Pythagoras, the hypotenuse is given by: hypotenuse2 = x2 + x2 = 2x2 Taking square roots, hypotenuse = sqrt(2x2) = sqrt(2)*x
Hypotenuse = 24
The formula for a 45-45-90 triangle is that both of the legs are n. The hypotenuse is n√2
No, the sum of the legs of a triangle have to be greater than the hypotenuse.
If a 45- 45- 90 triangle has a hypotenuse of length 18 units, the length of both of the other legs is: 12.73 units.
If it is a 45-45-90 triangle, it will have symmetry from the 90 degree angle to the midpoint of the hypotenuse.
The other sides are both 16. This is because in a 45-45-90 triangle the legs are congruent because of the isosceles triangle theorem, and also the hypotenuse of the triangle is equal to the leg times root 2. That is because of the 45-45-90 triangle theorem. So in a summary the legs are congruent and the hypotenuse is equal to the leg times root 2.
When it is an isosceles right angled triangle: with angles that are 90-45-45.
Using Pythagoras' theorem
It is a triangle whose interior angles are 45, 45 and 90 degrees
In a 45-45-90 triangle, both legs are congruent and the length of the hypotenuse is square root of 2 times the length of the leg.
Only if the angles of the triangle are 90, 45, and 45.
3v/2
4.95