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Q: How do you find the average of n numbers?

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To find the average of n numbers, take the sum of the numbers and divide by n.

To find the average of n numbers, sum the numbers and divide the sum by n. Thus for 4 numbers, divide their sum by 4.

The average is 10. You will find that the average when adding together the first n odd numbers is always equal to n.

The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.

For any set of numbers n-1, n, and n+1, the average will be n. For example, if the numbers are 18, 19, 20, the average will be 19.

Mean = (sum of the n numbers)/n

Average is the sum of numbers divided by n. It is also called the mean average.Here is an example to find the average of numbers:Let's say you want to find the average of four numbers, 26, 14, 11, and 9.First you need to add up those 4 numbers. 26 + 14 + 11 + 9 = 60.Then you need to divide the result (60), by the numbers of numbers there are, in this case 4, because there are four numbers you want to find the average.60 divided by 4 = 15, so the average of the numbers 26, 14, 11, and 9 is 15.

The answer is one million (the average of the first n odd numbers is always n.)

Any number can be the average. For example, 7 is the average of 7-n and 7+n for any number n.

Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550

Let the middle number of the three be n. Then the three consecutive numbers are n-1, n, n+1. Their sum is n-1 + n + n+1 = 3n Their average is 3n / 3 = n The difference between their sum and their average is 3n-n = 2n 2n = 156 => n = 78. Thus the three numbers are 77, 78, 79

Mean = Total of the numbers / n So total of the numbers = n*mean

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