answersLogoWhite

0


Best Answer

The average of n numbers = (sum of n numbers) / (count of n numbers).

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you find the average of n numbers?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Formula for finding the average?

To find the average of n numbers, take the sum of the numbers and divide by n.


What is the average of first 10 odd whole numbers?

The average is 10. You will find that the average when adding together the first n odd numbers is always equal to n.


What is average of first 100 even numbers?

The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.


The average of three consecutive numbers?

For any set of numbers n-1, n, and n+1, the average will be n. For example, if the numbers are 18, 19, 20, the average will be 19.


What is an average and how do you find it?

Average is the sum of numbers divided by n. It is also called the mean average.Here is an example to find the average of numbers:Let's say you want to find the average of four numbers, 26, 14, 11, and 9.First you need to add up those 4 numbers. 26 + 14 + 11 + 9 = 60.Then you need to divide the result (60), by the numbers of numbers there are, in this case 4, because there are four numbers you want to find the average.60 divided by 4 = 15, so the average of the numbers 26, 14, 11, and 9 is 15.


Find the mean of n natural numbers?

Mean = (sum of the n numbers)/n


Arithmetical average of the first one million odd numbers?

The answer is one million (the average of the first n odd numbers is always n.)


How would you find the sum of the first 50 even numbers?

Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550


Are 951008090 average numbers?

Any number can be the average. For example, 7 is the average of 7-n and 7+n for any number n.


The sum of three consecutive numbers is 156 more than their average what are these numbers?

Let the middle number of the three be n. Then the three consecutive numbers are n-1, n, n+1. Their sum is n-1 + n + n+1 = 3n Their average is 3n / 3 = n The difference between their sum and their average is 3n-n = 2n 2n = 156 => n = 78. Thus the three numbers are 77, 78, 79


How do you find median for index numbers?

Put them is ascending order. Count them = n. If n is odd, calculate (n+1)/2 the median is the value of the [(n+1)/2]th number in the ordered list. If n is even, the median is the average of the [n/2]th and [n/2 + 1]th numbers.


How can you find the total of the n numbers in a distribution if you know their mean?

Mean = Total of the numbers / n So total of the numbers = n*mean