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Sum of 1st n even numbers:

count*average = n * (2 + 2*n)/2 = n * (n+1)

Sum = 50 * (2+100)/2 = 50*51 = 2550

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Q: How would you find the sum of the first 50 even numbers?
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Find the sum of first 10 even numbers?

The sum of the first 10 even numbers is 110.


What happens to the median when you come up with two answer?

when you have an even amount of numbers while trying to find the median, you first find the two numbers that are at the median and then take all the numbers between them and find the median of that. if that amount of digits is also even, then you must have a decimal median.


If the sum of two consecutive even integers is -298 What are the integers?

-150, -148 To find these numbers set up an algebraic expression. The first even integer would be 2X and the next even integer would be 2X + 2 So, 2X + (2X+2) = -298 Solving for X, X = -75 So the first even integer would be 2*(-75) or -150 And the second even integer would be 2 + the first or 2+-150 or -148


The product of 2 consecutive even numbers is 840. Find the numbers?

Let the first even number be represented by (2x), where (x) is an integer. The next consecutive even number would then be (2x + 2). The product of these two numbers is (2x(2x + 2) = 4x^2 + 4x). Setting this equal to 840 gives us the quadratic equation (4x^2 + 4x - 840 = 0). Solving this equation yields (x = 10) and (x = -21), but since we are dealing with even numbers, the two consecutive even numbers are 20 and 22.


Consecutive even numbers that have the sum of 186?

Let's represent the first even number as x. The next consecutive even number would be x + 2. Since they are consecutive even numbers, their sum can be expressed as x + (x + 2) = 186. Simplifying this equation, we get 2x + 2 = 186. Solving for x, we find x = 92. Therefore, the consecutive even numbers are 92 and 94.