rearrange Pythagoras theorem equation to suit your dilemma
If you are given the length of 1 leg, L, and the altitude, A, the length of the base is the 2x square root of (L2 -A2 )
If you're only given the base, then you can't calculate the other leg. If you have any one of the following, then you can calculate all of the parts of the triangle: -- length of the other leg -- length of the hypotenuse -- size of either acute angle
The length of a midsegment is half that of the parallel side of the triangle; assuming the midsegment is parallel to the [given] base, then its length is 27 ÷ 2 = 13.5 units.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
The answer depends on whether the base is one of the legs of the right angle or the hypotenuse. Also, a triangle cannot have a diagonal.
If the given length is the measure length of the base of the triangle, then the area of the triangle is: A = (bh)/2 = (10 x 20)/2 = 100.
If you are given the length of 1 leg, L, and the altitude, A, the length of the base is the 2x square root of (L2 -A2 )
If you're only given the base, then you can't calculate the other leg. If you have any one of the following, then you can calculate all of the parts of the triangle: -- length of the other leg -- length of the hypotenuse -- size of either acute angle
The length of a midsegment is half that of the parallel side of the triangle; assuming the midsegment is parallel to the [given] base, then its length is 27 ÷ 2 = 13.5 units.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
The answer depends on whether the base is one of the legs of the right angle or the hypotenuse. Also, a triangle cannot have a diagonal.
The base is 2.5ft.
A triangle has three sides and three altitudes. Whatlength are you given ? ! ?If the triangle is standing up in the familiar position where the base is not one ofthe two equal sides, then the perimeter is(one of the equal sides) + (the other equal side) + (the base)If the length you're given happens to be the length of one of the equal sides,then the base is the only one of these three terms that you don't know yet.Do you think you can calculate it now ?
It depends if the triangle is 2D or 3D but most of the time you can. Look it up on Google. Just type in the question.
The answer depends on what information you do have about the triangle.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
If A = (b x h) ÷ 2, then h = 2A ÷ b, where A is the area of a triangle, b is the length of its base, and h is its height.