You can only do this if the two numbers won't be equal:
if(a > b)
return a;
else
return b;
yes
largest number a,b,c,d
Square biggest prime factor and divide original number by result. Does NOT work for some numbers, eg. 1600/24 etc.
Find your own answers....sucks mahn
int max (int a, int b) { return a>b?a:b; }
Answers down there. range: add the numbers all up and divide how many numbers you have. meadian: put all the numbers in order from smallest to biggest, then find the one in the middle. mean: the biggest minus the smallest. HOPE YOU GET AN A+!!! *************************************************______________________
Find the biggest common factor and divide it by both numbers
you take the biggest number and subtract it by the smallest number.
arg_cnt=$# arg_list=$* biggest=$1 if [ $arg_cnt -eq 0 ]; then echo "$RF there should be minimum 1 argument" exit 1 fi for each_arg in $arg_list do if [ $each_arg -gt $biggest ]; then biggest=$each_arg fi done echo " Biggest number is : $biggest \n" exit 0
program to find maximum of two numbers using pointers
The smallest is 0o0'0'' and the largest is 180o0'0''
Take the biggest number and subtract it by the smallest number