The cube root of a negative number is negative.
The cube root of a negative number is negative
It depend how many negative numbers are written on the cube.
You cannot get real square root of a negative number because two numbers multiplied by themselves are always positive You can always get a real cube root of a negative number because three negative numbers multiplied by themselves give a negative .
yes, you can find a real root to the cube root of any negative real number. There will also be two complex roots which satisfy it, as well.
Because if you multiply a negative number three times, the product will be negative.
there is no cube roots in negative
To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).
-53 = -125, which is nearest you can get since the cube of a negative number MUST be negative.
square and cube caculator
I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">
No, the cube root of -9 is an irrational number.
Of course negative. For example: (-4)^3 = (-4)*(-4)*(-4) = -64
Negative 2 (times) cube root of 54 = -7.55953 Negative 2 (plus) cube root of 54 = 1.77976
To cube a number, you would multiply the number three times. The cube root is the root of the number before it is multiplied. For example, 2 times 2 times 2 is 8, so the cube root is 2.
Do the number ^ (1/3). The number to the one-third power. It's the same as the cube root of the number.
minus the cube root of 2, or about -1.26
Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.
When two negative or two positive numbers are multiplied together, they always result in a positive number; and when a positive and a negative number are multiplied together, they will always result in a negative number. Thus, you cannot square root a negative number because there are no real numbers that, when squared, would result in a negative number. For example: (-2)(-2) = 4 (2)(2) = 4 √4 = +/- 2 √(-4) = ? No real number, when squared, is a negative! Does not exist! The cube of a number is different, because you are multiplying three numbers together instead of just two. As a result, you can get a negative or a positive number. For example: (-2)(-2)(-2) = -8r (2)(2)(2) = 8 3√8 = 2 3√(-8) = -2
592704 is the cube of 84. You can find the cube of any number by multiplying the number three times that is - 84 x 84 x 84.