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How do you find the cube root of a negative number?
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">
How Do You Find Integer On Math Problems?
An integer is any whole number. It could be positive, zero or negative.
The sum of the squares of two consecutive negative even integers is 100 find the integers?
The negative part is just a trick because any number squared, whether positive or negative, will turn out to be a positive number. But, to satisfy the question... -6*-6=36 -8*-8=64 36+64=100 tada. -6 and -8 would be the answer.
Why is square root of the number -9 not a real number?
Well, honey, the square root of a negative number like -9 isn't a real number because in the real number system, the square root of a negative number isn't defined. You gotta step into the world of complex numbers if you wanna play with those imaginary roots. So, in short, the square root of -9 is as real as a unicorn riding a rainbow.
How do you find antilog of a negative number using a log table?
Well, isn't that just a happy little question! To find the antilog of a negative number using a log table, you can start by taking the absolute value of the negative number to make it positive. Then, look up the positive number in the log table to find its corresponding antilog. Remember, there are no mistakes in math, just happy little accidents!
