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If it is a regular polygon you count the number of sides. Subtract two and multiply that by 180. Then you would divide your product by however many sides there are

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How do you find the measure of one exterior angle of a 15-gon?

remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree


How do you find the interior angle degree of a polygon?

(n-2)*180 = sum of interior angles when n is the number of sides of the polygon


How can you find the center of a regular polygon?

You can find the intersection of the angle bisectors or the intersection of the perpendicular bisectors of each side.


How do you find measure of each interior angles?

I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.


How do you find a missing angle of a polygon?

That will depend on how many sides the polygon has.

Related Questions

How do you find the measure of one exterior angle of a 15-gon?

remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree


The number of sides of a regular polygon is 7. Find the measure of each interior angle of the polygon?

a 7 sided polygon is heptagon and the interior angle of it is 128.57 degrees.


How do you find the interior angle degree of a polygon?

(n-2)*180 = sum of interior angles when n is the number of sides of the polygon


If the measure of each interior angle of a regular polygon is 171 find the number of sides in the polygon?

40 sides


What is the formula for finding the sum of an interior angle of a polygon?

(n-2)(180) use that formula to find the sum of the interior angles of a polygon in degree


Find the measures of an interior angle and an exterior angle of a regular polygon with 9 sides?

Each interior angle: 140 degrees Each exterior angle: 40 degrees


What is the measure of each angle in a 12 sided polygon?

This figure is a regular 12-sided polygon. Find m<4


What is the formula to find the measure of each interior angle of a regular polygon?

that's geometry so the formula to find the measure of each interior angle of a regular polygon is: Ia=stands for internal angle Ia=(n-2)180 ---------- n that's the formula.


What is degree measurement of an angle?

I need to know how to find each angle measured to the first degree. Such as: Sin B= 0.4848


How can you find the center of a regular polygon?

You can find the intersection of the angle bisectors or the intersection of the perpendicular bisectors of each side.


What is the formula to find the sum of the measures of the exterior angles one at each vertex of a polygon?

If it's a regular polygon: 360/number of sides = each exterior angle


What is the measure of each central angle in a 12-sided regular polygon?

This figure is a regular 12-sided polygon. Find m<4