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How do you find the measure of one exterior angle of a 15-gon?
remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree
How do you find the interior angle degree of a polygon?
(n-2)*180 = sum of interior angles when n is the number of sides of the polygon
How can you find the center of a regular polygon?
You can find the intersection of the angle bisectors or the intersection of the perpendicular bisectors of each side.
How do you find measure of each interior angles?
I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.
How do you find the measure of each interior angle in a polygram?
Total of interior angles of an n-sided polygon is 180n -360 or (2n -4) right angles. If the polygon is regular then each angle is the total obtained above divided by n.
How do you find the measure of one exterior angle of a 15-gon?
remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree
The number of sides of a regular polygon is 7. Find the measure of each interior angle of the polygon?
a 7 sided polygon is heptagon and the interior angle of it is 128.57 degrees.
How do you find the interior angle degree of a polygon?
(n-2)*180 = sum of interior angles when n is the number of sides of the polygon
If the measure of each interior angle of a regular polygon is 171 find the number of sides in the polygon?
40 sides
What is the formula for finding the sum of an interior angle of a polygon?
(n-2)(180) use that formula to find the sum of the interior angles of a polygon in degree
Find the measures of an interior angle and an exterior angle of a regular polygon with 9 sides?
Each interior angle: 140 degrees Each exterior angle: 40 degrees
What is the formula to find the measure of each interior angle of a regular polygon?
that's geometry so the formula to find the measure of each interior angle of a regular polygon is: Ia=stands for internal angle Ia=(n-2)180 ---------- n that's the formula.
What is the measure of each angle in a 12 sided polygon?
This figure is a regular 12-sided polygon. Find m<4
What is degree measurement of an angle?
I need to know how to find each angle measured to the first degree. Such as: Sin B= 0.4848
How can you find the center of a regular polygon?
You can find the intersection of the angle bisectors or the intersection of the perpendicular bisectors of each side.
What is the formula to find the sum of the measures of the exterior angles one at each vertex of a polygon?
If it's a regular polygon: 360/number of sides = each exterior angle
What is the measure of each central angle in a 12-sided regular polygon?
This figure is a regular 12-sided polygon. Find m<4
