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How do you find the measure of one exterior angle of a 15-gon?
remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree
How do you find the interior angle degree of a polygon?
(n-2)*180 = sum of interior angles when n is the number of sides of the polygon
How can you find the center of a regular polygon?
You can find the intersection of the angle bisectors or the intersection of the perpendicular bisectors of each side.
How do you find measure of each interior angles?
I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.
How do you find a missing angle of a polygon?
That will depend on how many sides the polygon has.
