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The derivative of f(x) is
lim h-->0 [f(x+h)-f(x)]/h.
So let f(x) = -5x. The derivative is
lim h-->0 [-5(x+h)- -5(x)]/h
= lim h-->0 [-5x - 5h + 5x]/h
= lim h-->0 -5h/h
Since the limit h-->0 of h/h is 1, the derivative is
-5
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∙ 11y ago
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How do you find the derivitive of an equation?
An equation may or may not have a derivative. The derivative of a function f(x), is usually defined as the limit as h tends to 0, of [f(x+h) - f(x)]/h
Formulae in derivative?
You will find several formulae in the Wikipedia article on "derivative".
What is the purpose of finding derivative?
The purpose of finding a derivative is to find the instantaneous rate of change. In addition, taking the derivative is used in integration by parts.
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The derivative of sin(x) is cos(x).
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You take the derivative using only one variable. The other variables act as constants.
How do you find the derivitive of an equation?
An equation may or may not have a derivative. The derivative of a function f(x), is usually defined as the limit as h tends to 0, of [f(x+h) - f(x)]/h
Formulae in derivative?
You will find several formulae in the Wikipedia article on "derivative".
What does the derivative at a point mean?
The derivative at any point in a curve is equal to the slope of the line tangent to the curve at that point. Doing it in terms of the actual expression of the curve, find the derivative of the curve, then plug the x-value of the point into the derivative to find the derivative at that point.
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All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2
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How do you find the second derivative?
Afetr you take the first derivative you take it again Example y = x^2 dy/dx = 2x ( first derivative) d2y/dx2 = 2 ( second derivative)
