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Let the base be x and use Pythagoras:

x2+(x+7)2 = (x+8)2

Multiply out the backets:

x2+x2+14x+49 = x2+16x+64

Rearrange all the terms into a quadratic equation:

x2-2x-15 = 0

Factorize:

(x+3)(x-5) = 0

x = -3 or x = 5 and in this case x must be 5

Therefore the dimensions are: hypotenuse 13 cm, height 12 cm and base 5 cm

Use the tangent ratio to find an interior angle:

tan-1(12/5) = 67.38013505 or 67 degrees

To find the other angle: 90-67 = 23 degrees

Therefore the interior angles are: 90 degrees, 67 degrees and 23 degrees

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Q: How do you find the dimensions and interior angles to the nearest degree of a right angle triangle when its hypotenuse is 8 cm greater than its base and with a height of 7 cm greater than its base?
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