This might be a long answer, but let's try.
Suppose the width, height, and length of the box are l, w, and h.
The area of one face is l*w.
The area of the second face is w*h.
The area of the third face is l*h.
Multiply these three equations together. Whatever the product is will be equal to l2w2h2.
Take the square root of this product to get lwh, the volume of the box.
There are only two dimensions given, so the volume is not attainable. However, the area (or surface area) of a rectangular face that is 10m by 20m is 200m2.
Each face of a cube is a square. If the edges are 3-ft, then the area of each square is 9 square feet.
If the length of each edge of the cube is 's',then the area of each face is s2.
Each face of a cube is a square. You simply square the length of each edge to find the area of the face. In this case, 4 inches squared = 4 x 4 which gives you 16 square inches per face.
the answer is 120
Using the dimensions you're given and those that you can calculate . . .-- Calculate and write down the area of each face of the pyramid.-- Then add up all of the individual areas.-- The sum is the surface area of the pyramid.
There are only two dimensions given, so the volume is not attainable. However, the area (or surface area) of a rectangular face that is 10m by 20m is 200m2.
A cube has 6 squares as the faces of a cube. The area of the square is A = s² where s is the length of the side. Given that area formula, we have: A = (3 centimeters)² = 9 centimeters² So the area of each face of a cube is 9 centimeters²
Each face of a cube is a square. If the edges are 3-ft, then the area of each square is 9 square feet.
If the length of each edge of the cube is 's',then the area of each face is s2.
They are the same so that each of the six faces has an equal probablility of landing face up.
Each face is 100 cm2 .
You find the area of each of its faces and add them together. Obviously, the area of each face will depend on its shape.
Each face of a cube is a square. You simply square the length of each edge to find the area of the face. In this case, 4 inches squared = 4 x 4 which gives you 16 square inches per face.
A regular octahedron has 8 faces. If the total surface area is 32 square inches then each face have a surface area equal to one eighth of this. 32/8 = 4 so the surface area of each face is 4 square inches
the answer is 120
The Perimeter