To increase the volume by a factor of 'X', the linear dimensions have to be
increased by a factor of (cube root of x).
Cube root of 2 = 1.26 (rounded)
So, make the box (2.52) x (7.56) x (5.04) .
Volume of the original box = (2 x 6 x 4) = 48 .
Volume of the new box = (2.52 x 7.56 x 5.04) = 96.018 (rounded)
2x3x5 6x5 30x2 =60 cubes
384
1100 is 60*7*76*76*60+70m well1202go tryutty99 is a user name are you kiding me?
As long as the cubes are 1x1x1 then any box with an equivalent volume would hold the same number of cubes. The volume of the 3x4x10 box is 120. So a box with the dimensions 1x1x120 would work just as well as a box with the dimensions 12x10x1 or 2x5x12.
7=84 --=-- 10=x 7x=840 ---=---- 7 = 7 x = 120 x equals how many oz 10 cubes can hold
2x3x5 6x5 30x2 =60 cubes
384
2 x 6 x 4 = 484 x 6 x 4 = 96
1100 is 60*7*76*76*60+70m well1202go tryutty99 is a user name are you kiding me?
7=84 --=-- 10=x 7x=840 ---=---- 7 = 7 x = 120 x equals how many oz 10 cubes can hold
As long as the cubes are 1x1x1 then any box with an equivalent volume would hold the same number of cubes. The volume of the 3x4x10 box is 120. So a box with the dimensions 1x1x120 would work just as well as a box with the dimensions 12x10x1 or 2x5x12.
Marshmallow because it is more absorbent.
That depends: * On the size of the 3D object * On the size of the cubes
2 cubes wide x 3 cubes long x 4 cubes high. 2 X 3 X4 6 X 4 24 cubes
30
25
72