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Q: How do you find the domain and range of f of x equals x squared minus 3x minus 10?

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The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.

Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.

D = {x [element of reals]}R = {y [element of reals]|y >= 4}

The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.

The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3

y is greater than 0 x exist in a set of real numbers

The domain could be the real numbers, in which case, the range would be the non-negative real numbers.

domain: all real numbers range: {5}

domain: (-infinity to infinity) range: ( -infinity to infinity)

The domain would be (...-2,-1,0,1,2...); the range: (12)

The Domain and Range are both the set of real numbers.

The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.

x

It depends on the domain but, if the domain is the real numbers, so is the range.

What is the domain and range of absolute lxl - 5

The domain and range are both [-6, +6].

The range depends on the domain.

The range depends on the domain, which is not specified.

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Domain is greater than or equal to zero. same with range

You can define the domain as anything you like and that will determine the range. Or, you can define the range as anything you like and that will determine the domain. For example: domain = {1, 2, 3, 4, ... } then range = {-3, 0, 5, 12, ... } or range = {1, 2, 3, 4, ... } then domain = {sqrt(5), sqrt(6), sqrt(7), sqrt(8), ...}. There is, of course, no need to restrict either set to integers but then it was easier to work out one set from the other.

It depends on the domain of x.

Domain : set of all reals Range: set of all reals

The domain and range of Y = 1.3x + 8 are both [-infinity, +infinity]

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