Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
What is the domain and range of absolute lxl - 5
(x^2)^(1/2) equals x, therefore, y = x+4, which has a range and domain of all real numbers. The graph is a straight line, slope of 1, y-intercept of 4. Are you actually saying y = (x^2+4)^(1/2). If so, the range and domain will also be all real numbers because x^2+4 will never result in a negative number.
-3
Assuming a large enough domain, the range is -1 to 1.
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
D = {x [element of reals]}R = {y [element of reals]|y >= 4}
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
What is the domain and range of absolute lxl - 5
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
The Domain and Range are both the set of real numbers.
all real numbers
The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.
The range depends on the domain, which is not specified.
It depends on the domain but, if the domain is the real numbers, so is the range.