Subtract the equation of one line from the equation of the other
The solution of a linear equation in two variable comprises the coordinates of all points on the straight line represented by the equation.
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
It's a linear equation in two variables . . . 'g' and 'p'. The graph of this equation is a straight line. The coordinates of every point on the line are a solution of the equation. There are an infinite number of them.
An equation of a line requires two parameters. The slope, by itself, is not enough.
Two coordinates are needed to determine the slope of a straight line equation.
This is a linear equation in two variables and the coordinates of each and every point on the line that it describes is a solution. A single linear equation does not have an "answer".
Since the slope of the line is 0, then the line is a horizontal line, and since the y-coordinates of the two points are 0, then the line lies on the x-axis. Thus, the equation of the line is y = 0.
"14" is not a point; you need two coordinates to specify a point.
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
A linear equation is that of a straight line. Any one of the infinitely many points on the line will be solutions. If the equation is in terms of the variables x and y, just pick any two values of x, solve for y and the results will be the coordinates of two solutions.