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How can you find the coordinates of two lines mathematically given the equation of both?
Subtract the equation of one line from the equation of the other
What is a solution of a linear equation in two variables?
The solution of a linear equation in two variable comprises the coordinates of all points on the straight line represented by the equation.
One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates?
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
How can you find an equation line between two pair of points?
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates.?
To find the equation of a line, you can start by identifying two points on the line, each represented by their coordinates (x₁, y₁) and (x₂, y₂). You can then calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Once you have the slope, you can use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to derive the line's equation. Finally, this can be rearranged into the slope-intercept form ( y = mx + b ) if needed.
How can find the equation of a line when given the x y coordinates?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
What is 5g plus 2 equals 4p-1?
It's a linear equation in two variables . . . 'g' and 'p'. The graph of this equation is a straight line. The coordinates of every point on the line are a solution of the equation. There are an infinite number of them.
How do you find the equation of a line by the slope?
An equation of a line requires two parameters. The slope, by itself, is not enough.
What is the slope -1 3 y-intercept 3?
Two coordinates are needed to determine the slope of a straight line equation.
What is answer x plus y equals 4?
This is a linear equation in two variables and the coordinates of each and every point on the line that it describes is a solution. A single linear equation does not have an "answer".
Write the equation for the line that passes through -1 0 and 5 0?
Since the slope of the line is 0, then the line is a horizontal line, and since the y-coordinates of the two points are 0, then the line lies on the x-axis. Thus, the equation of the line is y = 0.
Can you find an equation of the line containing the given pair of points 0 -6 and 4 2?
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
