answersLogoWhite

0


Best Answer

Taking the derivative:

2lnx+2, 2(lnx+1).

Extrema occur at y'=0.

2(lnx+1)=0,lnx=-1

x=e^(-1)=1/e

y=-2/e

So the extrema occurs at (1/e,-2/e)

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you find the extreme values of x2lnx?
Write your answer...
Submit
Still have questions?
magnify glass
imp