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The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
1) Find the least common multiple of 3, 4, and 5. 2) Divide the greatest possible 6-digit number (999,999) by this number. 3) Discard the decimal part, and multiply the result again by this greatest common factor.
Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.
It is easier to find the lowest common number, then getting the largest multiple of that that is under 10000. The LCM is 4680, x2 is 9360.
The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
1) Find the least common multiple of 3, 4, and 5. 2) Divide the greatest possible 6-digit number (999,999) by this number. 3) Discard the decimal part, and multiply the result again by this greatest common factor.
Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.
If the digit in the tens place is divisible by 2 and the digit in the units place is a 0, then the number is divisible by twenty.
the greatest 4 digit number=9999. the LCM of 24 and 28=168. dividing (9999 + 100)=10099 by 168 the remainder is 19. the required answer is 9999-19=9980
It is easier to find the lowest common number, then getting the largest multiple of that that is under 10000. The LCM is 4680, x2 is 9360.
Yes. 72 divided by 2 is 36. To find out if a number is divisible by 2 look at the last digit of the number. If it is even then the number is divisible by 2. For example 86 the lst digit is 6 which is an even number which means it is divisible by 2. yes, any even number is divisible by two.
100015
yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6
First we need to find the L.C.M. of 40, 48 and 60. 40 = 2x2x2x5 48 = 2x2x2x2x3 60 = 2x2x3x5 After taking out common factors, we have L.C.M. = 2x2x2x3x5x2 = 240 To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240. Remainder = 159 Subtracting this remainder from 9999 we get 9999 - 159 = 9840. So, the required answer is 9840.
Any number is divisble by all of those. Did you mean what is a NATURAL number divisible by those? That I am too lazy to find out.