Assuming that the given numbers are the second to fifth numbers of a sequence, any number can be the first (initial) number. It is easy to find a polynomial rule such that the first number is the chosen number, followed by the four numbers that are listed in the question. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
if t(n) = (35n^4 - 282n^3 + 904n^2 - 1125n + 480)/6 then t(1) = 2
if t(n) = (36n^4 - 396n^3 + 975n^2 - 1279n + 600)/6 then t(1) = 6
if t(n) = (37n^4 - 310n^3 + 1046n^2 - 1433n + 720)/6 then t(1) = 10
and so on.
Intermediate values of t(1) are, of course, possible: including fractions. But the coefficients for their rules are more complicated.
sequence
Store the numbers in a suitable container such as an array. Assume the first number is the smallest and assign its value to a local variable. Traverse the remainder of the sequence, comparing each element's value to the stored value. If an element has a lower value, assign its value to the local variable. When the sequence is fully traversed, the local variable will hold the value of the smallest value in the sequence. Return that value.
Depends on the sequence. There may be a formula for the Nth term in which case it is easy. Or the value may depend on some combination of previous terms (as in the Fibbonaci series).
The first step is to find the sequence rule. The sequence could be arithmetic. quadratic, geometric, recursively defined or any one of many special sequences. The sequence rule will give you the value of the nth term in terms of its position, n. Then simply substitute the next value of n in the rule.
A sequence xn is convergent, and converges to y if given any positive number d, however small, it is possible to find a value for the index k, such thatabs(xn - y) < d for all n > k.In other words, there is a value, k, such that all elements of the sequence from xk will be closer to y than an arbitrarily small value.
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
The sequence number on your boarding pass can typically be found near your seat assignment or boarding group information. It is usually a numerical value that helps determine the order in which passengers will board the plane.
Someone looking for a sequence diagram online can find them at various websites. Microsoft is a website which has sequence diagrams. There are many other websites dedicated to sequence diagrams.
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
http://www.farfarfar.com/math/calculators/sequence/