I'm sure someone could supply the actual theorem or rule but it could logically be any one of the factors. Like an area of eighteen could have a l and w of 1 and 18 or 2 and 9, I think.
Square root the area. The length and width of a square are always the same and length times width is the area so this is how you get the area.
It is the same as its length, and if that is not given, it is the square root of the area.
For a rectangle or square, Area = Length * Width So Length = Area / Width.
For a given perimeter, its a square.
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
Square root the area. The length and width of a square are always the same and length times width is the area so this is how you get the area.
i think you find the square root of the area. that's the length and the width, so you multiply it.
length = 484/width
Just multiply the length times the width.
It is the same as its length, and if that is not given, it is the square root of the area.
The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.
For a rectangle or square, Area = Length * Width So Length = Area / Width.
For a given perimeter, its a square.
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
You cannot calculate the length and width of a room on its area alone. You could compute the square root of the area on the assumption that the room has a square shape, but you'd generally need the ratio of length over width.
If the area is already given, there should also be either width or length given. Do the area, divided by the length or the width. For example, the area divided by the width equal the length. Hope it helps.
Given the area, you need also the length if you want to calculate the width. The width can also be expressed as width = 300/blank.