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How do you find the length of the straight line y equals 17 -3x that joins the curve y equals x squared plus 2x -7?
Wiki User
∙ 13y ago
First find the points where the straight line meets with the curve:
x2+2x-7 = 17-3x
x2+2x+3x-7-17 = 0
x2+5x-24 = 0
Solving the above by means of the quadratic equation formula gives x values of -8 and 3
when x = 3, y = 8 and when x = -8, y = 41
(x2-x1)2+(y2-y1)2 = (line length)2
(-8-3)2+(41-8)2 = 1210 and its square root is the length of the line
Length = 11 times the square root of 10 which is about 34.785 units of length
Wiki User
∙ 13y ago
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The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
What is the value of k when the straight y equals 3x-1 is a tangent to the curve x squared plus y squared equals k?
2
What is the length of the line y equals 8 -x that meets the curve of y equals x squared plus 4x plus 2 at two distinctive points?
7*sqrt(2) = 9.899 to 3 dp
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k = 0.1
Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
What is the length of the line x -y equals 2 that spans the curve x squared - 4y squared equals 5?
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
What is the value of k when the straight y equals 3x-1 is a tangent to the curve x squared plus y squared equals k?
2
At what point is the line of y equals x -4 tangent to the curve of x squared plus y squared equals 8?
(2, -2)
What is the value of k when y equals 3x plus 1 is a line tangent to the curve of x squared plus y squared equals k hence finding the point of contact of the line to the curve?
It is (-0.3, 0.1)
What is the length of the line y equals 8 -x that meets the curve of y equals x squared plus 4x plus 2 at two distinctive points?
7*sqrt(2) = 9.899 to 3 dp
What is the value of k when y equals 3x plus 1 and is a line tangent to the curve of x squared plus y squared equals k?
k = 0.1
What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
What is the length of the two straight parts of the track?
On a 400m track, each straight length is 100m, as well as each curve is 100m, totaling 400.
Where are the points of intersection of the straight line 3x -y equals 5 with the curve 2x squared plus y squared equals 129?
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.
What are the coordinates of the line x-y equals 2 that intersects the of curve x squared-4y squared equals 5?
If you mean the coordinates of the line x-y = 2 that intersects the curve of x2-4y2 = 5 Then the coordinates work out as: (3, 1) and (7/3, 1/3)
What is the length of the line of y equals 17 -3x that spans the curve of y equals x squared plus 2x -7?
If you mean: y = 17-3x and y = x^2+2x-7 then the length of the line works out as 11 times square root of 10 or about 34.785 to three decimal places.
Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
