-- In the equation of the graph, set x=0.
-- Solve the equation for 'y'.
-- The value you get for 'y' when x=0 is the y-intercept.
The magnitude of a vector is a geometrical value for hypotenuse.. The magnitude is found by taking the square root of the i and j components.
There is no slope nor intercept because there is no equation, simply an expression.
"Magnitude" is the size or distance. Its measure depends on the metric that is defined on the relevant space.
The magnitude is the length of the vector (using any scaling factor that may have been employed).
Use trigonometry.
Actually you answer itself is wrong. You can only find the magnitude of force, not the magnitude in force. You can find the magnitude of force by s = (1/2)*a*t^2
The magnitude of a vector is a geometrical value for hypotenuse.. The magnitude is found by taking the square root of the i and j components.
Just remove the minus sign (if there is one), and what remains is the magnitude.
There is no slope nor intercept because there is no equation, simply an expression.
"Magnitude" is the size or distance. Its measure depends on the metric that is defined on the relevant space.
The magnitude is the length of the vector (using any scaling factor that may have been employed).
m=m_v
Use trigonometry.
First find the phase crossover frequency and then use that back into the magnitude of the transfer function.Then the gain margin is the reciprocal of that magnitude.
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
1.307
Find an expression for the magnitude of the horizontal force in the figure for which does not slip either up or down along the wedge. All surfaces are frictionless.