An isosceles triangle can be split up into two right angle triangles so use trigonometry to find the base and then double your answer to find the base of the isosceles triangle which works out as 57.12592026 meters.
Base = 20/tan(35) = 28.56296013
Base of isosceles = 28.56296013*2 = 57.12592026
Area = 1/2*base*height
Area = 1/2*57.12592026*20 = 571.2592026 square meters
No because the maximum lines of symmetry a triangle can have is 3 as an equilateral triangle and 1 as an isosceles triangle otherwise a triangle has no lines of symmetry.
Any triangle can have a maximum of one right angle. Most right triangles are scalene triangles. The only non-scalene right triangle is a 45° - 45° - 90° isosceles right triangle. It is not possible to have an equilateral right triangle in plane geometry. A scalene triangle does not have to have a right angle, but it can have one.
A triangle can only have a maximum of 1 right angle. The total degrees of all the angles of a triangle adds up to exactly 180. Since a triangle must have exactly three angles, it is not possible for the triangle to have more than one angle that is 90 degrees.
The maximum area is just under 3.9 sq feet [exactly (3/2)2*sqrt(3) sq ft] - an area that is attained by an equilateral triangle. Since the question specifies an isosceles triangle, the answer is very very slightly less than that.
No. The maximum are is attained when it is equilateral and that is less than 7 cm2
an isosceles triangle can have any vertex angle less than 180 and greater than 0, as long the other two angles are equal. an isosceles triangle with a vertex of 179 degrees would just have the other two angles be 0.5 degrees. A right triangle with matching angles (both 45 degrees) would be both a right triangle and isosceles triangle.
It can only have a maximum of one- and that is only if it is a right-angled isosceles triangle. ----------------------------------------------------- Yes not all isosceles triangles are right angle triangles - this is a special case.
It can only have a maximum of one- and that is only if it is a right-angled isosceles triangle. ----------------------------------------------------- Yes not all isosceles triangles are right angle triangles - this is a special case.
No because the maximum lines of symmetry a triangle can have is 3 as an equilateral triangle and 1 as an isosceles triangle otherwise a triangle has no lines of symmetry.
Any triangle can have a maximum of one right angle. Most right triangles are scalene triangles. The only non-scalene right triangle is a 45° - 45° - 90° isosceles right triangle. It is not possible to have an equilateral right triangle in plane geometry. A scalene triangle does not have to have a right angle, but it can have one.
A triangle can only have a maximum of 1 right angle. The total degrees of all the angles of a triangle adds up to exactly 180. Since a triangle must have exactly three angles, it is not possible for the triangle to have more than one angle that is 90 degrees.
The maximum area is just under 3.9 sq feet [exactly (3/2)2*sqrt(3) sq ft] - an area that is attained by an equilateral triangle. Since the question specifies an isosceles triangle, the answer is very very slightly less than that.
No. The maximum are is attained when it is equilateral and that is less than 7 cm2
6 maximum points of intersection
The minimum length possible is 18. The maximum is 38.
The largest possible triangle is an equilateral triangle. Here's a sort of proof - try making some sketches to get the idea. * For any given isosceles triangle ABC that you might inscribe, where AB = BC... * ...Moving vertex A to be perpendicularly above the midpoint of BC will increase the area, since its distance from BC (the height of the triangle) will be at a maximum.* This gives a new isosceles, where AB = AC. * The same thing applies to the new isosceles. You can keep increasing the area in this way until the process makes no difference. If the process can increase the area no further, it can only be because all the vertices are already above the midpoints of the opposite edges. Which means we have an equilateral triangle. Anyhow, to answer the question, an equilateral triangle inscribed in a circle of radius r will have side length d where d2 = 2r2 - 2r2cos(120) from the cosine rule. and since cos(120) = -1/2 d2 = 2r2 + r2 = 3r2 and so d = r sqrt(3) *Equally, move vertex C above the midpoint of AB.
The maximum latitude is 90 degrees north or south.