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How do you find the missing width in surface area?

Updated: 8/21/2019
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9y ago

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Answer depends on what the shape is and what other information is available.

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9y ago
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Q: How do you find the missing width in surface area?
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Related questions

How do you find a surface area?

Lenght X width = surface area


How can you find the surface area of a rectangular area?

It is length * width.


Who do you find the surface area of a rectangle?

Surface area = length*width in square units


Can you find the surface area on a sheet of paper?

To find the area, multiply the height by the width.


How do you find surface area of a rectancle?

Hight X Width


How do you find the missing length in a rectangle?

That will depend on the information given as for example if you are given its width and area then in order to find its length divide the width into the area.


What is the formula to find the surface area of a rectangle?

Length X Width.


How do you find the height of a box given the width depth and surface area?

divide surface area by width Sorry It is a little more complicated than that. Surface area = (2 X length X width) + (2 X length X height) + (2 X width X height) Solve for height Surface area - (2 X length X width) = 2height(length + width) (Surface area - (2 X length X width))/2(length + width) = height


How do you do surface area in the fifth grade?

You usually find the area by length*width, that is how I was taught.


How do you find the surface area of a rectangular prism if you are missing a dimension?

You cannot.


How do you find length and width with just the height and surface area?

To get the surface area, someone had to multiply length times width. So what we would need to do is take our surface area, divide by our height, which is our width, and get our length. So if SA stood for surface area, and h stood for height, we'd take SA/h to get the length.


How do you find the area of something using width length depth?

Area is a plane or surface measurement. Depth is not required. Multiply the length by the width.