Each exterior angle of a regular polygon with n sides has the angular measure of 360 degrees/(n - 2). A polygon has the same number of sides as angles, so that the total angular measure S of all the exterior angles will be 360 n/(n - 2); S(n - 2) = 360 n;
nS - 2S = 360 n; n(S - 360) = 2S; n = (2S)/(S - 360).
A regular 10 polygon
A regular polygon will have 360 sides with exterior angles of 181 degrees.
10
9
The sum of the exterior angles of a polygon = 360360 / 36 = 10 degrees
5 sides and it is a regular pentagon
taco
For any polygon, regular or otherwise, the sum of exterior angles is always 3600.
The sum of the exterior angles of a polygon equals 360.Quadrilateral has 4 exterior angles.360/4=90 for a regular quadrilateral.
It is: 40 degrees
180
30 degrees