If the two legs are 7 units, this being a right angled triangle, by Pythagoras, the hypotenuse will be 7*sqrt(2) = 9.90 units long.
Then the periimeter is 7+7+9.90 = 23.90 units.
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).
P = x3 + sqroot(x*x + x2*x2) x3 is the combined length of the two sides. Using pythagorean theory we find the hypotenuse, and add it to the other two sides to find the perimeter.
that's easy...you just have to add 6 and 12. then you multiply the 6 times the radical 3 which is approximately 1.7. so 6+12=18 then 1.7x6=10.2. then you add 18 and 10.2 and you get 28.2. so the perimeter of the triangle is about 28.2 you would write it out like this: sides: 6+12+√3 perimeter: 18+√3= 28.2
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
Length of longer leg = 9.4 tan 60 = 16.28 feet Length of hypotenuse = 9.4 ÷ cos 60 = 18.8 feet Perimeter of triangle = 9.4 + 16.28 + 18.8 = 44.48 feet
12
The perimeter is equal to the sum of (leg-1) plus (leg-2) plus (hypotenuse).
Legs are 'x' and '4x'.Hypotenuse is sqrt(17x2) = x sqrt(17)Perimeter = x [ 5 + sqrt(17) ]
P = x3 + sqroot(x*x + x2*x2) x3 is the combined length of the two sides. Using pythagorean theory we find the hypotenuse, and add it to the other two sides to find the perimeter.
Using Pythagoras' theorem the other leg is 45 inches So: 51+24+45 = 120 Perimeter = 120 inches
It depends on what measure you want: the perimeter, the area, the size of the angles or something else. The question is not specific enough.
That depends on what x is: a leg, an angle, what?
that's easy...you just have to add 6 and 12. then you multiply the 6 times the radical 3 which is approximately 1.7. so 6+12=18 then 1.7x6=10.2. then you add 18 and 10.2 and you get 28.2. so the perimeter of the triangle is about 28.2 you would write it out like this: sides: 6+12+√3 perimeter: 18+√3= 28.2
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.